Converting a triple integral from rectangular coordinates to cylindrical coordinates require to change the function f(x,y,z) in cylindrical form i.e f(r,θ,z). Let's model this through an example.
Example
Solution
We have to transform the given triple integral in cylindrical coordinates form. Let's use the Fubini's theorem:
In polar form, we have x = rcosθ y = rsinθ.
Let's find for the limits of integration for r, θ and z. The limits of integration of x and y from the given integral are:
Let's solve the system of inequalities:
−1 ≤ y ≤ 1
0 ≤ x ≤ √(1 − y2)
Since x ≥ 0 and √(1 − y2) ≥ 0, we can square the inequality x ≤ √(1 − y2):
x ≤ √(1 − y2) ⟺ x2 ≤ 1 − y2 ⟺ x2 + y2 ≤ 1.
Therefore the solution set is
{ (x, y) ∈ ℝ2 : x ≥ 0 and x2 + y2 ≤ 1 }.
Geometrically, this is the right half of the closed unit disk (including the boundary).
In polar form we have:
0 ≤ r ≤ 1, −π/2 ≤ θ ≤ π/2.
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